remove None value from a list without removing the 0 value
>>> L = [0, 23, 234, 89, None, 0, 35, 9]>>> [x for x in L if x is not None][0, 23, 234, 89, 0, 35, 9]Just for fun, here's how you can adapt filter to do this without using a lambda, (I wouldn't recommend this code - it's just for scientific purposes)
>>> from operator import is_not>>> from functools import partial>>> L = [0, 23, 234, 89, None, 0, 35, 9]>>> filter(partial(is_not, None), L)[0, 23, 234, 89, 0, 35, 9]
A list comprehension is likely the cleanest way:
>>> L = [0, 23, 234, 89, None, 0, 35, 9>>> [x for x in L if x is not None][0, 23, 234, 89, 0, 35, 9]There is also a functional programming approach but it is more involved:
>>> from operator import is_not>>> from functools import partial>>> L = [0, 23, 234, 89, None, 0, 35, 9]>>> list(filter(partial(is_not, None), L))[0, 23, 234, 89, 0, 35, 9]
Using list comprehension this can be done as follows:
l = [i for i in my_list if i is not None]The value of l is:
[0, 23, 234, 89, 0, 35, 9]