Return copy of dictionary excluding specified keys
You were close, try the snippet below:
>>> my_dict = {... "keyA": 1,... "keyB": 2,... "keyC": 3... }>>> invalid = {"keyA", "keyB"}>>> def without_keys(d, keys):... return {x: d[x] for x in d if x not in keys}>>> without_keys(my_dict, invalid){'keyC': 3}Basically, the if k not in keys will go at the end of the dict comprehension in the above case.
In your dictionary comprehension you should be iterating over your dictionary (not k , not sure what that is either). Example -
return {k:v for k,v in d.items() if k not in keys}
This should work for you.
def without_keys(d, keys): return {k: v for k, v in d.items() if k not in keys}