Running an outside program (executable) in Python?

If using Python 2.7 or higher (especially prior to Python 3.5) you can use the following:

import subprocess

• subprocess.call(args, *, stdin=None, stdout=None, stderr=None, shell=False)Runs the command described by args. Waits for command to complete, then returns the returncode attribute.
• subprocess.check_call(args, *, stdin=None, stdout=None, stderr=None, shell=False)Runs command with arguments. Waits for command to complete. If the return code was zero then returns, otherwise raises CalledProcessError. The CalledProcessError object will have the return code in the returncode attribute

Example: subprocess.check_call([r"C:\pathToYourProgram\yourProgram.exe", "your", "arguments", "comma", "separated"])

In regular Python strings, the \U character combination signals a extended Unicode code point escape.

Here is the link to the documentation: http://docs.python.org/3.2/library/subprocess.html

For Python 3.5+ you can now use run() in many cases: https://docs.python.org/3.5/library/subprocess.html#subprocess.run

Those whitespaces can really be a bother. Try os.chdir('C:/Documents\ and\ Settings/') followed by relative paths for os.system, subprocess methods, or whatever...

If best-effort attempts to bypass the whitespaces-in-path hurdle keep failing, then my next best suggestion is to avoid having blanks in your crucial paths. Couldn't you make a blanks-less directory, copy the crucial .exe file there, and try that? Are those havoc-wrecking space absolutely essential to your well-being...?

The simplest way is:

import osos.startfile("C:\Documents and Settings\flow_model\flow.exe")

It works; I tried it.