Scrape the absolute URL instead of a relative path in python

In this case urlparse.urljoin helps you. You should modify your code like this-

import bs4 as bs4import urllib.requestfrom urlparse import  urljoinweb_url = 'https:www.example-page-xl.com'sauce = urllib.request.urlopen(web_url).read()soup = bs.BeautifulSoup(sauce,'lxml')section = soup.sectionfor url in section.find_all('a'):    print urljoin(web_url,url.get('href'))

here urljoin manage absolute and relative paths.

urllib.parse.urljoin() might help. It does a join, but it is smart about it and handles both relative and absolute paths. Note this is python 3 code.

>>> import urllib.parse>>> base = 'https://www.example-page-xl.com'>>> urllib.parse.urljoin(base, '/helloworld/index.php') 'https://www.example-page-xl.com/helloworld/index.php'>>> urllib.parse.urljoin(base, 'https://www.example-page-xl.com/helloworld/index.php')'https://www.example-page-xl.com/helloworld/index.php'

I see the solution mentioned here to be the most robust.

import urllib.parsedef base_url(url, with_path=False):    parsed = urllib.parse.urlparse(url)    path   = '/'.join(parsed.path.split('/')[:-1]) if with_path else ''    parsed = parsed._replace(path=path)    parsed = parsed._replace(params='')    parsed = parsed._replace(query='')    parsed = parsed._replace(fragment='')    return parsed.geturl()