Selenium Finding elements by class name in python
You can try to get the list of all elements with class = "content"
by using find_elements_by_class_name:
a = driver.find_elements_by_class_name("content")
Then you can click on the link that you are looking for.
As per the HTML:
<html> <body> <p class="content">Link1.</p> </body><html><html> <body> <p class="content">Link2.</p> </body><html>
Two(2) <p>
elements are having the same class content
.
So to filter the elements having the same class i.e. content
and create a list you can use either of the following Locator Strategies:
Using
class_name
:elements = driver.find_elements_by_class_name("content")
Using
css_selector
:elements = driver.find_elements_by_css_selector(".content")
Using
xpath
:elements = driver.find_elements_by_xpath("//*[@class='content']")
Ideally, to click on the element you need to induce WebDriverWait for the visibility_of_all_elements_located()
and you can use either of the following Locator Strategies:
Using
CLASS_NAME
:elements = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.CLASS_NAME, "content")))
Using
CSS_SELECTOR
:elements = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, ".content")))
Using
XPATH
:elements = WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//*[@class='content']")))
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWaitfrom selenium.webdriver.common.by import Byfrom selenium.webdriver.support import expected_conditions as EC
References
You can find a couple of relevant discussions in:
- How to identify an element through classname even though there are multiple elements with the same classnames using Selenium and Python
- Unable to locate element using className in Selenium and Java
- What are properties of find_element_by_class_name in selenium python?
- How to locate the last web element using classname attribute through Selenium and Python