Specify color of each point in scatter plot (matplotlib)

If you don't want to use a for loop (which can be very slow for large lists) You can use the scatter command as is with an RGB color list, but you need to specify the colors as a vector of RGB (or RGBA) values between 0 and 1

X = [0, 1, 2]Y = [0, 1, 2]Z = [0, 1, 2]C = np.array([[255, 0, 0], [0, 255, 0], [0, 0, 255]])fig = plt.figure()ax = fig.add_subplot(111, projection = '3d')ax.scatter(X, Y, Z, c = C/255.0)plt.show()

I used a for loop to individually assign each color to each point. Here is my code:

X = [1, 2, 3]Y = [2, 5, 8]Z = [6, 4, 5]colors=["#0000FF", "#00FF00", "#FF0066"]fig = plt.figure()ax = fig.add_subplot(111, projection = '3d')for i in range(len(X)):    ax.scatter(X[i], Y[i], Z[i], color=colors[i])plt.show()

The for loop goes point by point (hence the [i] in front of each X,Y,Z value) and gives a color one by one. I used hex colors for my example, but you could probably use something else if you wanted.

Here is an example where the colors are calculated instead of specified by a literal list.

import matplotlib.pyplot as pltimport numpy as npphi = np.linspace(0, 2*np.pi, 60)x = np.sin(phi)y = np.cos(phi)rgb_cycle = np.vstack((            # Three sinusoids    .5*(1.+np.cos(phi          )), # scaled to [0,1]    .5*(1.+np.cos(phi+2*np.pi/3)), # 120° phase shifted.    .5*(1.+np.cos(phi-2*np.pi/3)))).T # Shape = (60,3)fig, ax = plt.subplots(figsize=(3,3))ax.scatter(x,y, c=rgb_cycle, s=90)fig.show()