Many-To-Many

In order to support a child having zero or more dogs and a dog belonging to zero or more children, your database table structure needs to support a Many-To-Many relationship. This requires three tables:

CREATE TABLE child (    id INTEGER PRIMARY KEY AUTOINCREMENT,    name TEXT);CREATE TABLE dog (    id INTEGER PRIMARY KEY AUTOINCREMENT,    dog TEXT);CREATE TABLE child_dog {    child_id INTEGER,    dog_id INTEGER,    FOREIGN KEY(child_id) REFERENCES child(id),    FOREIGN KEY(dog_id) REFERENCES dog(id)};

How to Insert

An insert into each of the three tables must be separate SQL statements, but can take place in the context of same transaction. Inserts into the child_dog table (known as the mapping table) must happen after inserts into the child and dog tables. This is for two related reasons:

1. You need to know the identifiers of both the child and the dog in order toto insert into this table.
2. Because of the foreign key constraint, an insert into the child_dog table would fail if the child and/or dog referenced do not exist in the database or transaction.

Here are some example SQL statements for insert:

INSERT INTO child VALUES(NULL, 'bobby');SELECT last_insert_rowid(); -- gives the id of bobby, assume 2 for this exampleINSERT INTO dog VALUES(NULL, 'spot');SELECT last_insert_rowid(); -- gives the id of spot, assume 4 for this exampleINSERT INTO child_dog VALUES(2, 4);

Inserting In Python

Although your question did not mention python, there is a python tag on this question so I'll assume you want to know how to do this in python. The sqlite3 module in python provides a nice little shortcut which saves you from having to run the 'last_insert_rowid()' function explicitly.

# Import the sqlite3 moduleimport sqlite3# Create a connection and cursor to your databaseconn = sqlite3.connect('example.db')c = conn.cursor()# Insert bobbyc.execute("""INSERT INTO child VALUES(NULL, 'bobby')""")# The python module puts the last row id inserted into a variable on the cursorbobby_id = c.lastrowid# Insert spotc.execute("""INSERT INTO dog VALUES(NULL, 'spot')""")spot_id = c.lastrowid# Insert the mappingc.execute("""INSERT INTO child_dog VALUES(?, ?)""", (bobby_id, spot_id));# Commitconn.commit()conn.close()

you need to have three tables for this. This is an example of Many-to-Many Relationship.

Child- ChildID (PK)- NameDog- DogID   (PK)- DogNameChild_Dog- ChildID (FK)   - DogID   (FK)