Strip HTML from strings in Python
I always used this function to strip HTML tags, as it requires only the Python stdlib:
For Python 3:
from io import StringIOfrom html.parser import HTMLParserclass MLStripper(HTMLParser): def __init__(self): super().__init__() self.reset() self.strict = False self.convert_charrefs= True self.text = StringIO() def handle_data(self, d): self.text.write(d) def get_data(self): return self.text.getvalue()def strip_tags(html): s = MLStripper() s.feed(html) return s.get_data()
For Python 2:
from HTMLParser import HTMLParserfrom StringIO import StringIOclass MLStripper(HTMLParser): def __init__(self): self.reset() self.text = StringIO() def handle_data(self, d): self.text.write(d) def get_data(self): return self.text.getvalue()def strip_tags(html): s = MLStripper() s.feed(html) return s.get_data()
I haven't thought much about the cases it will miss, but you can do a simple regex:
re.sub('<[^<]+?>', '', text)
For those that don't understand regex, this searches for a string <...>
, where the inner content is made of one or more (+
) characters that isn't a <
. The ?
means that it will match the smallest string it can find. For example given <p>Hello</p>
, it will match <'p>
and </p>
separately with the ?
. Without it, it will match the entire string <..Hello..>
.
If non-tag <
appears in html (eg. 2 < 3
), it should be written as an escape sequence &...
anyway so the ^<
may be unnecessary.
You can use BeautifulSoup get_text()
feature.
from bs4 import BeautifulSouphtml_str = '''<td><a href="http://www.fakewebsite.com">Please can you strip me?</a><br/><a href="http://www.fakewebsite.com">I am waiting....</a></td>'''soup = BeautifulSoup(html_str)print(soup.get_text()) #or via attribute of Soup Object: print(soup.text)
It is advisable to explicitly specify the parser, for example as BeautifulSoup(html_str, features="html.parser")
, for the output to be reproducible.