Unzipping files in Python
If you are using Python 3.2 or later:
import zipfilewith zipfile.ZipFile("file.zip","r") as zip_ref: zip_ref.extractall("targetdir")You dont need to use the close or try/catch with this as it uses thecontext manager construction.
zipfile is a somewhat low-level library. Unless you need the specifics that it provides, you can get away with shutil's higher-level functions make_archive and unpack_archive.
make_archive is already described in this answer. As for unpack_archive:
import shutilshutil.unpack_archive(filename, extract_dir)unpack_archive detects the compression format automatically from the "extension" of filename (.zip, .tar.gz, etc), and so does make_archive. Also, filename and extract_dir can be any path-like objects (e.g. pathlib.Path instances) since Python 3.7.