What exactly is a "raw string regex" and how can you use it?

Zarkonnen's response does answer your question, but not directly. Let me try to be more direct, and see if I can grab the bounty from Zarkonnen.

You will perhaps find this easier to understand if you stop using the terms "raw string regex" and "raw string patterns". These terms conflate two separate concepts: the representations of a particular string in Python source code, and what regular expression that string represents.

In fact, it's helpful to think of these as two different programming languages, each with their own syntax. The Python language has source code that, among other things, builds strings with certain contents, and calls the regular expression system. The regular expression system has source code that resides in string objects, and matches strings. Both languages use backslash as an escape character.

First, understand that a string is a sequence of characters (i.e. bytes or Unicode code points; the distinction doesn't much matter here). There are many ways to represent a string in Python source code. A raw string is simply one of these representations. If two representations result in the same sequence of characters, they produce equivalent behaviour.

Imagine a 2-character string, consisting of the backslash character followed by the n character. If you know that the character value for backslash is 92, and for n is 110, then this expression generates our string:

s = chr(92)+chr(110)print len(s), s2 \n

The conventional Python string notation "\n" does not generate this string. Instead it generates a one-character string with a newline character. The Python docs 2.4.1. String literals say, "The backslash (\) character is used to escape characters that otherwise have a special meaning, such as newline, backslash itself, or the quote character."

s = "\n"print len(s), s1  

(Note that the newline isn't visible in this example, but if you look carefully, you'll see a blank line after the "1".)

To get our two-character string, we have to use another backslash character to escape the special meaning of the original backslash character:

s = "\\n"print len(s), s2 \n

What if you want to represent strings that have many backslash characters in them? Python docs 2.4.1. String literals continue, "String literals may optionally be prefixed with a letter 'r' or 'R'; such strings are called raw strings and use different rules for interpreting backslash escape sequences." Here is our two-character string, using raw string representation:

s = r"\n"print len(s), s2 \n

So we have three different string representations, all giving the same string, or sequence of characters:

print chr(92)+chr(110) == "\\n" == r"\n"True

Now, let's turn to regular expressions. The Python docs, 7.2. re — Regular expression operations says, "Regular expressions use the backslash character ('\') to indicate special forms or to allow special characters to be used without invoking their special meaning. This collides with Python’s usage of the same character for the same purpose in string literals..."

If you want a Python regular expression object which matches a newline character, then you need a 2-character string, consisting of the backslash character followed by the n character. The following lines of code all set prog to a regular expression object which recognises a newline character:

prog = re.compile(chr(92)+chr(110))prog = re.compile("\\n")prog = re.compile(r"\n")

So why is it that "Usually patterns will be expressed in Python code using this raw string notation."? Because regular expressions are frequently static strings, which are conveniently represented as string literals. And from the different string literal notations available, raw strings are a convenient choice, when the regular expression includes a backslash character.

Questions

Q: what about the expression re.compile(r"\s\tWord")? A: It's easier to understand by separating the string from the regular expression compilation, and understanding them separately.

s = r"\s\tWord"prog = re.compile(s)

The string s contains eight characters: a backslash, an s, a backslash, a t, and then four characters Word.

Q: What happens to the tab and space characters? A: At the Python language level, string s doesn't have tab and space character. It starts with four characters: backslash, s, backslash, t . The regular expression system, meanwhile, treats that string as source code in the regular expression language, where it means "match a string consisting of a whitespace character, a tab character, and the four characters Word.

Q: How do you match those if that's being treated as backlash-s and backslash-t? A: Maybe the question is clearer if the words 'you' and 'that' are made more specific: how does the regular expression system match the expressions backlash-s and backslash-t? As 'any whitespace character' and as 'tab character'.

Q: Or what if you have the 3-character string backslash-n-newline? A: In the Python language, the 3-character string backslash-n-newline can be represented as conventional string "\\n\n", or raw plus conventional string r"\n" "\n", or in other ways. The regular expression system matches the 3-character string backslash-n-newline when it finds any two consecutive newline characters.

N.B. All examples and document references are to Python 2.7.

Update: Incorporated clarifications from answers of @Vladislav Zorov and @m.buettner, and from follow-up question of @Aerovistae.

Most of these questions have a lot of words in them and maybe it's hard to find the answer to your specific question.

If you use a regular string and you pass in a pattern like "\t" to the RegEx parser, Python will translate that literal into a buffer with the tab byte in it (0x09).

If you use a raw string and you pass in a pattern like r"\t" to the RegEx parser, Python does not do any interpretation, and it creates a buffer with two bytes in it: '\', and 't'. (0x5c, 0x74).

The RegEx parser knows what to do with the sequence '\t' -- it matches that against a tab. It also knows what to do with the 0x09 character -- that also matches a tab. For the most part, the results will be indistinguishable.

So the key to understanding what's happening is recognizing that there are two parsers being employed here. The first one is the Python parser, and it translates your string literal (or raw string literal) into a sequence of bytes. The second one is Python's regular expression parser, and it converts a sequence of bytes into a compiled regular expression.

The issue with using a normal string to write regexes that contain a \ is that you end up having to write \\ for every \. So the string literals "stuff\\things" and r"stuff\things" produce the same string. This gets especially useful if you want to write a regular expression that matches against backslashes.

Using normal strings, a regexp that matches the string \ would be "\\\\"!

Why? Because we have to escape \ twice: once for the regular expression syntax, and once for the string syntax.

You can use triple quotes to include newlines, like this:

r'''stuff\things'''

Note that usually, python would treat \-newline as a line continuation, but this is not the case in raw strings. Also note that backslashes still escape quotes in raw strings, but are left in themselves. So the raw string literal r"\"" produces the string \". This means you can't end a raw string literal with a backslash.

See the lexical analysis section of the Python documentation for more information.