Find file name from full file path

Use

basename("C:/some_dir/a.ext")# [1] "a.ext"dirname("C:/some_dir/a.ext")# [1] "C:/some_dir"

file r path

The tidyverse equivalent lives in the fs package. {fs} makes use of libuv under the hood.

library("fs")path_file("/some/path/to/file.xyz")#> [1] "file.xyz"path_dir("/some/path/to/file.xyz")#> [1] "/some/path/to"

^{Created on 2020-02-19 by the reprex package (v0.3.0)}

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