How logical negation operator "!" works

First, it's probably best not to think of != as ! acting on =, but rather as a separate binary operator altogether.

In general, ! should only be applied to boolean vectors. So this is probably more like what you are after:

vector1 <- 1:5 # just making vector of 5 numbersvector2 <- 5:1 # same vector backwardsl <- list(Forward=vector1, Backwards=vector2) # producing list with two elementsx = "Forward"l[!(names(l) %in% x)]

where names(l) %in% x returns a boolean vector along the names of the list l indicating whether they are contained in x or not. Finally, I avoided the use of list as a variable, since you can see it is a fairly common function as well.

I agree with everything said by the other two posters, but want to add one more thing I always tell when teaching R.

R works in that it evaluates statements from the inside to the outside and each of those statements needs to run on it's own. If you already have an error in an inner statement, no wonder the outers do not produce anything.

In your case one could say you have two statements: !x and list accessing on list via [.

If you replicate R's behavior you notice that !x already produces the error:

> !xError in !x : invalid argument type

Hence, the correct solutions try to change this step.

So: Always check your innermost statements when an errors occurs and work yourself outwards.

First, I think the ! in != is not the ! operator. It is a distinct, != operator, which means "different from".

Second, the ! operator is a logical one, the logical negation, and it must be applied to a logical vector :

R> !(c(TRUE,FALSE))[1] FALSE  TRUE

As numbers can be coerced to logical, it can also be applied to a numerical vector. In this case 0 will be considered as FALSE and any other value as TRUE :

R> !c(1,0,-2.5)[1] FALSE  TRUE FALSE

In your example, you are trying to apply this logical operator to a character string, which raises an error.

If you want to subset lists, data frames or vectors by names, indices or conditions, you should read and learn about the indexing part of the R language, which is described in the R manuals and most of the introductory books and documents.

One way to subset a list by names could be, for example :

R> list[!(names(list) %in% "Forward")]$Backwards[1] 5 4 3 2 1