dom ready event in React dom ready event in React reactjs reactjs

dom ready event in React


TL;DR If I understand correctly, the answer is probably "not possible". But there is another solution...

Here's what I think you're trying to do, described as a series of steps:

  1. page starts loading, <Loader /> component shows a "page loading" animation

  2. page finishes loading, <Loader /> component is removed (or hidden) and <Page /> component is inserted (or shown) with the "real" page content.

Here's the problem: remember that you inject your React components into the page like this:

ReactDOM.render(<Wrapper />, document.getElementById('app'));

You can't actually inject a React component until the DOM is loaded. So by that time, either <Loader /> appears for about 2 milliseconds and disappears, or it doesn't appear at all (since the DOM is already loaded by the time it gets injected into the page).

If you're trying to show a throbber or other simple animation (like an animated GIF), I'd try a hybrid approach:

Set up your HTML like this:

<body>    <div id="app"><img src="throbber.gif" /></div></body>

In your script tag, include a JQuery "document ready" event handler to load the React component:

class Page extends Component {}class Wrapper extends Component {    render() {        return (            <Page />        );    }}$(document).ready(function () {    ReactDOM.render(<Wrapper />, document.getElementById('app'));});

Notice that I've left out the <Loader /> - the throbber image is doing the work of the loader.

The idea here is that while the page is loading, the throbber GIF will be throbbing away until the DOM is loaded, at which point JQuery's document ready event will fire & the contents of the div#app will be replaced.

I haven't tried this, but it should work, provided that React actually replaces the content of div#app, rather than just appending stuff to it. If that's not the case, then it's a simple matter of changing the document ready handler to something like this:

$(document).ready(function () {    $('div#app img').remove();    ReactDOM.render(<Wrapper />, document.getElementById('app'));});


The approach I ended up using (No JQuery needed) is the following:

In the index.html, put the loader element right after the root div

<div id="root"></div><div id="preloader" class="pre-loader">  <img src="..."> </img></div>

Then inside your index.js :

document.addEventListener("DOMContentLoaded", function(event) {     ReactDOM.render(    <React.StrictMode>      <Provider store={store}>    <BrowserRouter>      <DashApp />    </BrowserRouter>    </Provider>    </React.StrictMode>,    document.getElementById("root")  );  const loadingScreen = document.getElementById("preloader");   loadingScreen.style.opacity = 0;   loadingScreen.style.display = "none";});

So basically we simply follow a similar approach to what the other answer suggests, but without the need of JQuery cause we listen to the loading event using

document.addEventListener("DOMContentLoaded", function(event) { }

Another approach would be just placing the loader inside the root div which means React will overwrite it by default when it loads:

<div id="root">  <div id="preloader" class="pre-loader">    <img src="..."> </img>  </div></div>   

My personal full approach can be seen in this