A way to round Floats down
1.9999.to_i#=> 11.9999.floor#=> 1answered 1 sec ago fl00r
"%.2f" % 1.93213#=> 1.93@kimmmo is right.
class Float def round_down(n=0) self.to_s[/\d+\.\d{#{n}}/].to_f endend
Based on answer from @kimmmo this should be a little more efficient:
class Float def round_down n=0 s = self.to_s l = s.index('.') + 1 + n s.length <= l ? self : s[0,l].to_f endend1.9991.round_down(3) => 1.9991.9991.round_down(2) => 1.991.9991.round_down(0) => 1.01.9991.round_down(5) => 1.9991or based on answer from @steenslag, probably yet more efficient as there is no string conversion:
class Float def round_down n=0 n < 1 ? self.to_i.to_f : (self - 0.5 / 10**n).round(n) endend
Looks like you just want to strip decimals after n
class Float def round_down(n=0) int,dec=self.to_s.split('.') "#{int}.#{dec[0...n]}".to_f endend1.9991.round_down(3) => 1.9991.9991.round_down(2) => 1.991.9991.round_down(0) => 1.01.9991.round_down(10) => 1.9991(Edit: slightly more efficient version without the regexp)