Convert a string date format from "17-Nov-2011" to "11/17/11"
Use the built-in Time.parse and Time#strftime functions.
require 'time'time = Time.parse("17-Nov-2011")time.strftime("%m/%d/%y")# => "11/17/11"
With Date#strftime you can format a date. Date.strptime allows you a 'reverse' action: Build a date from string.
When you combine both, you get your result:
puts Date.strptime('17-Nov-2011', '%d-%b-%Y').strftime('%m/%d/%y')Each %-Parameters is a part of the date string.You need:
For parsing the date string:
- %d: number of the day (17)
- %b: Month with three letters (Nov)
- %Y: Year with 4 digits (2011)
For creating the string:
- %m: Month (11)
- %d: number of the day (17)
- %y: Year with 2 digits (11)
Ruby has a pretty robust set of date and time functions, check out the Date class.
Date.parse("17-Nov-2011").strftime('%m/%d/%y')