Ruby: Deleting all instances of a particular key from hash of hashes
Really, this is what reject! is for:
def f! x x.reject!{|k,v| 'inner' == k} if x.is_a? Hash x.each{|k,v| f! x[k]}end
def f x x.inject({}) do |m, (k, v)| v = f v if v.is_a? Hash # note, arbitrarily recursive m[k] = v unless k == 'inner' m endendp f hUpdate: slightly improved...
def f x x.is_a?(Hash) ? x.inject({}) do |m, (k, v)| m[k] = f v unless k == 'inner' m end : xend
def except_nested(x,key) case x when Hash then x = x.inject({}) {|m, (k, v)| m[k] = except_nested(v,key) unless k == key ; m } when Array then x.map! {|e| except_nested(e,key)} end xend