Click on random link in webpage using selenium API for python
find_elements_by_tagname() will surely work. There is another option also. You can use find_elements_by_partial_link_text where you can pass empty string.
>>> from selenium import webdriver>>> from random import randint>>> driver = webdriver.Firefox()>>> driver.get('http://www.python.org')>>> links = driver.find_elements_by_partial_link_text('')>>> l = links[randint(0, len(links)-1)]>>> l.click()
driver = webdriver.Firefox()driver.get('https://www.youtube.com/watch?v=hhR3DwzV2eA')# store the current url in a variablecurrent_page = driver.current_url# create an infinite loopwhile True: try: # find element using css selector links = driver.find_elements_by_css_selector('.content-link.spf-link.yt-uix-sessionlink.spf-link') # create a list and chose a random link l = links[randint(0, len(links) - 1)] # click link l.click() # check link new_page = driver.current_url # if link is the same, keep looping if new_page == current_page: continue else: # break loop if you are in a new url break except: continueCreating a list work, but if you are having problems like me use this code if you keep getting Timeout Error or your webdriver isn't consistently clicking the link.
As an example I used a YT video. Say you want to click a recommended video on the right side, well, it has a unique css selector for those links.
The reason why you want to make an infinite loop is b/c when when you make a list of elements, for some reason, python doesn't do a good job expressing stored elements. Be sure you have a catch all 'except' b/c you will get Timeout Errors and such and you want to force it to click on the random link.
How about generating a list of all available links on the page and then clicking a random element from within that list?
list = driver.find_elements_by_tagname("a")list[random.Random(0, len(list)].click()(I hope that's how you use random in python 2.7, I'm a python 3.3 user, sorry)