Getting text from a node

You can't do this in the WebDriver API, you have to do it in your code. For example:

var textOfA = theAElement.getText();var textOfSpan = theSpanElement.getText();var text = textOfA.substr(0, textOfA.length - textOfSpan.length).trim('\n');

Note that the trailing newline is actually part of the text of the <a> element, so if you don't want it, you need to strip it.

Here is the method developed in python.

def get_text_exclude_children(element):    return driver.execute_script(        """        var parent = arguments[0];        var child = parent.firstChild;        var textValue = "";        while(child) {            if (child.nodeType === Node.TEXT_NODE)                textValue += child.textContent;                child = child.nextSibling;        }        return textValue;""",        element).strip()

How to use in this:

liElement = driver.find_element_by_xpath("//a[@href='your_href_goes_here']")liOnlyText = get_text_exclude_children(liElement)print(liOnlyText)

Please use your possible strategy to get the element, this method need an element from which you need the text (without children text).

If using Python:

[x['textContent'].strip() for x in element.get_property('childNodes') if isinstance(x, dict)]

Where element is your element.

This will return ['Title', ''] (because there are spaces after span).