How to check if an alert is open using nodejs webdriver (wd)
This may help - this is how I detect an alert using Selenium Webdriver for node.js:
var webdriver = require('selenium-webdriver');var url = "http://web-page-to-test-for-alert";driver = new webdriver.Builder(). withCapabilities(webdriver.Capabilities.chrome()). build();driver.get(url);driver.switchTo().alert().then( function() { console.log("alert detected"); }, function() { console.log("no alert detected"); });driver.quit(); 'then' is related to promises: then(success, failure)
and this may also help - it's how I ignore any alert that presents on a page:
function ignoreAlert(driver) { // detect and accept any alert driver.switchTo().alert().then(function() { driver.switchTo().alert().accept();}, function(){});}
Make sure to set ignoreSynchronization if you're navigating to a non angular app:
browser.ignoreSynchronization = true;browser.get(url);browser.switchTo().alert().then(function() { browser.switchTo().alert().accept();}, function(){});browser.ignoreSynchronization = false;