how to get src of image using XPATH in selenium python
find_elements will return list so use find_element.
imgsrc= driver.find_element_by_xpath("//img[contains(@class,'_3me- _3mf1 img')]")x=imgsrc.get_attribute("src")print(x)or if you want to use find_elements try this.
imgsrc= driver.find_elements_by_xpath("//img[contains(@class,'_3me- _3mf1 img')]")for ele in imgsrc: x=ele.get_attribute("src") print(x)
From your code trials presumably you are trying to print the src attributes of the <img> elements having the class attribute as _3me-, _3mf1 and img. But the class attributes _3me- and _3mf1 are not static and are dynamically generated. So as a closest bet you can use either of the following Locator Strategies:
CSS_SELECTOR:print([ele.get_attribute("src") for ele in WebDriverWait(driver, 30).until(EC.visibility_of_all_elements_located((By.CSS_SELECTOR, "img.img")))])XPATH:print([ele.get_attribute("src") for ele in WebDriverWait(driver, 30).until(EC.visibility_of_all_elements_located((By.XPATH, "//img[contains(@class, 'img')]")))])