Python and Selenium - Avoid submit form when send_keys() with newline

Did you tried something like:

ActionChains(driver).key_down(Keys.SHIFT).key_down(Keys.ENTER).key_up(Keys.SHIFT).key_up(Keys.ENTER).perform()

Like

from selenium import webdriverfrom selenium.webdriver.common.keys import Keysfrom selenium.webdriver.common.action_chains import ActionChainsdriver = webdriver.Chrome()driver.get('http://foo.bar')inputtext = 'foo\nbar'elem = driver.find_element_by_tag_name('div')for part in inputtext.split('\n'):    elem.send_keys(part)    ActionChains(driver).key_down(Keys.SHIFT).key_down(Keys.ENTER).key_up(Keys.SHIFT).key_up(Keys.ENTER).perform()

ActionChains will chain key_down of SHIFT + ENTER + key_up after being pressed.

Like this you perform your SHIFT + ENTER, then release buttons so you didn't write all in capslock (because of SHIFT)

PS: this example add too many new lines (because of the simple loop on inputtext.split('\n'), but you got the idea.

This is the method I actively use. At least this is simpler.

from selenium import webdriverdriver = webdriver.Chrome()driver.get('http://foo.bar')text = "any\ntext"textarea = webdriver.find_element_by_xpath('//*[@id="main"]/footer/div[1]/div[2]/div/div[2]') #find elementif '\r\n' in text: #check if exists \n tag in text    textsplit = text.split("\r\n") #explode    textsplit_len = len(textsplit)-1 #get last element    for text in textsplit:        textarea.send_keys(text)        if textsplit.index(text) != textsplit_len: #do what you need each time, if not the last element            textarea.send_keys(Keys.SHIFT+Keys.ENTER)