BASH scripting: n-th parameter of $@ when the index is a variable? BASH scripting: n-th parameter of $@ when the index is a variable? shell shell

BASH scripting: n-th parameter of $@ when the index is a variable?


bash shell argv

You can use variable indirection. It is independent of arrays, and works fine in your example:

n=2echo "${!n}"

Edit: Variable Indirection can be used in a lot of situations. If there is a variable foobar, then the following two variable expansions produce the same result:

$foobarname=foobar${!name}

bash shell argv

Try this:

#!/bin/bashargs=("$@")echo ${args[1]}

okay replace the "1" with some $n or something...

bash shell argv

The following works too:

#!/bin/bashn=2echo ${@:$n:1}

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