Bash: start date less than equal to end date
With dateutils' datetest this is simple:
$ datetest 2014-11-1 --le 2016-01-1 ; echo $?0$ datetest 2014-11-1 --gt 2016-01-1 ; echo $?1Then again, what you want is simply done by dateseq, which also happens to be a tool of the dateutils suite.
$ dateseq 2014-11-1 +1mo 2016-01-12014-11-012014-12-012015-01-012015-02-012015-03-012015-04-012015-05-012015-06-012015-07-012015-08-012015-09-012015-10-012015-11-012015-12-012016-01-01Disclaimer: I am the author of the package.
-le is for numeric data. 2014-11-01 is not a number. Use < or >. (You need to escape them as \< or \>. Or use [[ instead of [.)
effectively, change
while [ "$m" != "$enddate" ]; doto
until [ "$m" \> "$enddate" ]; door
until [ "$m" '>' "$enddate" ]; door
until [[ "$m" > "$enddate" ]]; doAlternately, use seconds since epoch instead of ISO8601 format.
while [ "$(date -d "$m" +%s)" -le "$(date -d "$enddate" +%s)" ]; do