exit function stack without exiting shell

To exit the function stack without exiting shell one can use the command:

kill -INT $$

As pizza stated, this is like pressing Ctrl-C, which will stop the current script from running and drop you down to the command prompt.

Note: the only reason I didn't select pizza's answer is because this was buried in his/her answer and not answered directly.

you can do a

exit() { return $1;}

then

source ./your_script 

In answer to the skeptics, this only affect the current shell, it does not affect shells you spawn.

The more informative form can be

exit() {    local ans    local line    read -p "You really want to exit this? " line    ans=$(echo $line)    case "$ans" in            Y);;            y);;            *)kill -INT $$;;    esac    unset -f exit    exit $1}

You'll need to add return statements to each of your functions to check the return value of any functions they call in turn. Sourcing a file is like cutting and pasting the code into the current context, with the minor exception of variables like $BASH_SOURCE.

Alternatively you could define fn as a shell script, so that exit will do what you want (unless a fork is too expensive).