files with same name in different folders

For simple things maybe will be enough the next syntax:

cat ./**/1.txt

or you can simply write

cat ./{A,B,C}/1.txt

e.g.

$ mkdir -p A C B/BB$ touch ./{A,B,B/BB,C}/1.txt$ touch ./{A,B,C}/2.txt

gives

./A/1.txt./A/2.txt./B/1.txt./B/2.txt./B/BB/1.txt./C/1.txt./C/2.txt

and

echo ./**/1.txt

returns

./A/1.txt ./B/1.txt ./B/BB/1.txt ./C/1.txt

cat ./**/1.txt

will run the cat with the above arguments... or,

echo ./{A,B,C}/1.txt

will print

./A/1.txt ./B/1.txt ./C/1.txt #now, without the B/BB/1.txt

and so on...

linux bash file shell scripting

Try this to get the files which have names in common:

cd dir1find . -type f | sort > /tmp/dir1.txtcd dir2find . -type f | sort > /tmp/dir2.txtcomm -12 /tmp/dir1.txt /tmp/dir2.txt

Then use a loop to do whatever you need:

for filename in "$(comm -12 /tmp/dir1.txt /tmp/dir2.txt)"; do    cat "dir1/$filename"    cat "dir2/$filename"done

linux bash file shell scripting

Will loop through all files in folder A, and if a file in B with same name exists, will cat both:

for fA in A/*; do    fB=B/${f##*/}    [[ -f $fA && -f $fB ]] && cat "$fA" "$fB"done

Pure bash, except the cat part, of course.

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