GAWK Script - Print filename in BEGIN section GAWK Script - Print filename in BEGIN section shell shell

GAWK Script - Print filename in BEGIN section


linux bash shell awk gawk

you can use ARGV[1] instead of FILENAME if you really want to use it in BEGIN block

awk 'BEGIN{print ARGV[1]}' file

linux bash shell awk gawk

You can print the file name when encounter line 1:

FNR == 1

If you want to be less cryptic, easier to understand:

FNR == 1 {print}

UPDATE

My first two solutions were incorrect. Thank you Dennis for pointing it out. His way is correct:

FNR == 1 {print FILENAME}

linux bash shell awk gawk

Straight from the man page (slightly reformatted):

FILENAME: The name of the current input file. If no files are specified on the command line, the value of FILENAME is “-”. However, FILENAME is undefined inside the BEGIN block (unless set by getline).

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