How can I strip first X characters from string using sed? How can I strip first X characters from string using sed? shell shell

How can I strip first X characters from string using sed?


bash shell sed

The following should work:

var="pid: 1234"var=${var:5}

Are you sure bash is the shell executing your script?

Even the POSIX-compliant

var=${var#?????}

would be preferable to using an external process, although this requires you to hard-code the 5 in the form of a fixed-length pattern.

bash shell sed

Here's a concise method to cut the first X characters using cut(1). This example removes the first 4 characters by cutting a substring starting with 5th character.

echo "$pid" | cut -c 5-

bash shell sed

Use the -r option ("use extended regular expressions in the script") to sed in order to use the {n} syntax:

$ echo 'pid: 1234'| sed -r 's/^.{5}//'1234

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