How to count number of files and subdirectories with shellscript?

How about using a find like this:

Files="$(find . -type f -maxdepth 1 -printf x | wc -c)"Directories="$(find . -type d -maxdepth 1 -printf x | wc -c)"

The Directories will also include the root directory (.)

I suggest two changes: eliminate the unnecessary files variable, and use a glob instead of parsing the output of ls. Then use the -d test to see if each directory entry is a directory (if it's not, assume it's a regular file, unless you really care about distinguishing named pipes, character devices, block devices, etc) and use the $((...)) expression for arithmetic.

echo "What absolute directory do you want to count?"read DIRcd "$DIR" || exitfile=0dir=0for d in *;do    if [ -d "$d" ]; then        dir=$((dir+1))    else        file=$((file+1))    fidoneecho "Files $file"echo "Directories $dir"

This can be done exactly in 3 lines:

read -p " Please enter the directory you want to count its files & subdirectories = " pathecho "Number of directories in $path =  "$(find $path/* -type d | wc -l)echo "Number of Files in $path = "$(find $path/* -type f | wc -l)