How to delete from a text file, all lines that contain a specific string?

To remove the line and print the output to standard out:

sed '/pattern to match/d' ./infile

To directly modify the file – does not work with BSD sed:

sed -i '/pattern to match/d' ./infile

Same, but for BSD sed (Mac OS X and FreeBSD) – does not work with GNU sed:

sed -i '' '/pattern to match/d' ./infile

To directly modify the file (and create a backup) – works with BSD and GNU sed:

sed -i.bak '/pattern to match/d' ./infile

There are many other ways to delete lines with specific string besides sed:

AWK

awk '!/pattern/' file > temp && mv temp file

Ruby (1.9+)

ruby -i.bak -ne 'print if not /test/' file

Perl

perl -ni.bak -e "print unless /pattern/" file

Shell (bash 3.2 and later)

while read -r linedo  [[ ! $line =~ pattern ]] && echo "$line"done <file > omv o file

GNU grep

grep -v "pattern" file > temp && mv temp file

And of course sed (printing the inverse is faster than actual deletion):

sed -n '/pattern/!p' file

You can use sed to replace lines in place in a file. However, it seems to be much slower than using grep for the inverse into a second file and then moving the second file over the original.

e.g.

sed -i '/pattern/d' filename      

or

grep -v "pattern" filename > filename2; mv filename2 filename

The first command takes 3 times longer on my machine anyway.