How to intercept and remove a command line argument in bash
This should work:
# Run older ld (pseudo condition)if [ <old_ld_condition> ]; then ARGS=() for var in "$@"; do # Ignore known bad arguments [ "$var" != '-dependency_info' ] && ARGS+=("$var") done /path/to/old/ld "${ARGS[@]}"else /path/to/new/ld "$@"fi
You should use Bash Arrays if you really want to stay with bash:
declare -a ARGSfor var in "$@"; do # Ignore known bad arguments if [ "$var" = '-dependency_info' ]; then continue fi ARGS[${#ARGS[@]}]="$var"donenow "${ARGS[@]}" can be used just as "$@". man bash for more information.