Print dates in date range linux
As long as the dates are in YYYY-MM-DD format, you can compare them lexicographically, and let date do the calendar arithmetic without converting to seconds first:
startdate=2013-03-15enddate=2013-04-14curr="$startdate"while true; do echo "$curr" [ "$curr" \< "$enddate" ] || break curr=$( date +%Y-%m-%d --date "$curr +1 day" )doneWith [ ... ], you need to escape the < to avoid confusion with the input redirection operator.
This does have the wart of printing the start date if it is greater than the end date.
Another option is to use dateseq from dateutils (http://www.fresse.org/dateutils/#dateseq):
$ dateseq 2013-03-01 2013-03-252013-03-012013-03-022013-03-032013-03-042013-03-052013-03-062013-03-072013-03-082013-03-092013-03-102013-03-112013-03-122013-03-132013-03-142013-03-152013-03-162013-03-172013-03-182013-03-192013-03-202013-03-212013-03-222013-03-232013-03-242013-03-25