Shell script to copy and prepend folder name to files from multiple subdirectories

I would use something like this:

find -type f -exec sh -c 'f={}; fnew=$(rev <<< "$f" | sed 's~/~_~' | rev); echo "mv $f $fnew"' \;

This looks for files within the current directory structure and perform the following:

• get the file name
• replace the last / with _.
• write echo "cp $old_file $new_file"

Once you have run this and seen it prints the proper command, remove the echo so that it effectively does the mv command.

I know the fnew=$(rev <<< "$f" | sed 's~/~_~' | rev) is a bit ugly trick, but I couldn't find a better way to replace the last / with _. Maybe sed -r 's~/([^/]*)$~_\1~' could also be appropiate, but I always like using rev :)

Since your find does not behave well with the -sh c expression, let's use a while loop for it:

while read -r filedo    new_file=$(rev <<< "$file" | sed 's~/~_~' | rev)    echo "mv $file $new_file"; done < <(find . -type f)done < <(find . -type f)

As a one-liner:

while read -r file; do new_file=$(rev <<< "$file" | sed 's~/~_~' | rev); echo "mv $file $new_file"; done < <(find . -type f)

functions to the rescue, updating Jahid's script:

function updateFolder{    mkdir "$2"    for folder in "$1"/*; do    if [[ -d $folder ]]; then        foldername="${folder##*/}"        for file in "$1"/"$foldername"/*; do            filename="${file##*/}"            newfilename="$foldername"_"$filename"            cp "$file" "$2"/"$newfilename"        done    fi    done}

used:

$ updateFolder /parent /newfolder

This is a bit tedious but will do:

#!/bin/bashparent=/parentnewfolder=/newfoldermkdir "$newfolder"for folder in "$parent"/*; do  if [[ -d "$folder" ]]; then    foldername="${folder##*/}"    for file in "$parent"/"$foldername"/*; do      filename="${file##*/}"      newfilename="$foldername"_"$filename"      cp "$file" "$newfolder"/"$newfilename"    done  fidone

Put the parent path to parent variable and newfolder path to newfolder variable.