Simple way to colour alternate output lines in bash
Not very pretty but does the trick:
(save this to foo.bash and do grep whatever wherever | ./foo.bash)
#!/bin/bashwhile read linedo echo -e "\e[1;31m$line" read line echo -e "\e[1;32m$line"doneecho -en "\e[0m"Here you can find the list of color codes in bash.
Perl is installed on many systems. You could have it alternate for you:
grep -r whatever somedir/ | perl -pe '$_ = "\033[1;29m$_\033[0m" if($. % 2)'In Perl $. can be substituted with $INPUT_LINE_NUMBER if you prefer readability.
This is to delineate wrapped lines I presume?This shell script uses a background color from the 256 color palette,so as not to interfere with other highlighting that grep --color might do.
#!/bin/shc=0while read line; do [ $(($c%2)) -eq 1 ] && printf "\033[48;5;60m" printf "%s\033[0m\n" "$line" c=$(($c+1))doneThis has the caveat that backslashes etc. within the line will be mangled,so treat this as pseudo code for reimplementation