How to search string LIKE 'something%' with Java Spring Framework?

Wait, of course I had to "try one more final thing" before calling it a day, and lo and behold, all my unit tests suddenly pass:

public List<Foo> getByName(List<Integer> codes, String namePart) {    String sql = "select * from FOO where CODE in (:codes) and NAME like :name"    Map<String,Object> params = new HashMap<String,Object>();    params.put("codes", codes);    params.put("name", namePart+"%");    return getSimpleJdbcTemplate().query(sql, new FooRowMapper(), params);}

I didn't think of entering the "%" in the parameter, I was certain Spring would automatically escape it. I wonder if I'm doing it right?

For named parameters to work, you need to use NamedParameterJdbcTemplate

params.put("name", "Joe%");jdbcTemplate.query("select * from FOO where CODE in (:codes) and NAME like :name" 

In another form, I encountered the same problem, and I tried to solve it via this manner:

public List<MyEntity> getMyEntityValuesBySearchText(String searchText) {    String query = "SELECT * FROM MY_ENTITY_TABLE WHERE NAME LIKE ?";    return this.getJdbcTemplate().query(query, new String[] { "%" + searchText + "%" },                (rs, rowNum) -> new MyEntity(rs.getLong("PK"), rs.getString("NAME")));}