JOIN two SELECT statement results JOIN two SELECT statement results sql sql

JOIN two SELECT statement results


sql select join group-by 

SELECT t1.ks, t1.[# Tasks], COALESCE(t2.[# Late], 0) AS [# Late]FROM     (SELECT ks, COUNT(*) AS '# Tasks' FROM Table GROUP BY ks) t1LEFT JOIN    (SELECT ks, COUNT(*) AS '# Late' FROM Table WHERE Age > Palt GROUP BY ks) t2ON (t1.ks = t2.ks);

sql select join group-by

Try something like this:

SELECT * FROM(SELECT ks, COUNT(*) AS '# Tasks' FROM Table GROUP BY ks) t1 INNER JOIN(SELECT ks, COUNT(*) AS '# Late' FROM Table WHERE Age > Palt GROUP BY ks) t2ON t1.ks = t2.ks

sql select join group-by

Use UNION:

SELECT ks, COUNT(*) AS '# Tasks' FROM Table GROUP BY ksUNIONSELECT ks, COUNT(*) AS '# Late' FROM Table WHERE Age > Palt GROUP BY ks

Or UNION ALL if you want duplicates:

SELECT ks, COUNT(*) AS '# Tasks' FROM Table GROUP BY ksUNION ALLSELECT ks, COUNT(*) AS '# Late' FROM Table WHERE Age > Palt GROUP BY ks

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