Can I cause Xcode's debugger to break programmatically?
For Swift, raise(SIGINT) works for me.
I have this function:
func fail(desc: String) { #if DEBUG print("assertFail:\(desc)") raise(SIGINT) #endif}For DEBUG macro setup see here: In absence of preprocessor macros, is there a way to define practical scheme specific flags at project level in Xcode project
Putting asm("svc 0") in your code will stop your running application if debugging through xcode. See: https://stackoverflow.com/a/34078247/215400
I'm not 100% positive there isn't a built in one - but you can create what you want yourself using Symbolic Breakpoints in the XCode UI.
1) Create a new class to represent your Debugger Break.
@interface MYDebuggerBreak : NSObject+(void)fireUpDebugger;@end@implementation MyDebuggerBreak+(void)fireUpDebugger { // Do Nothing}@end2) Add a Symbolic Breakpoint to a method on that Class
[MYDebuggerBreak fireUpDebugger]This is a bit roundabout, you could also put a breakpoint directly into the line "fireUpDebugger" since you control the code. Symbolic Breakpoints are more useful if you want to stop on a method call for something you don't control.