How to create a fixed-size array of objects

Fixed-length arrays are not yet supported. What does that actually mean? Not that you can't create an array of n many things — obviously you can just do let a = [ 1, 2, 3 ] to get an array of three Ints. It means simply that array size is not something that you can declare as type information.

If you want an array of nils, you'll first need an array of an optional type — [SKSpriteNode?], not [SKSpriteNode] — if you declare a variable of non-optional type, whether it's an array or a single value, it cannot be nil. (Also note that [SKSpriteNode?] is different from [SKSpriteNode]?... you want an array of optionals, not an optional array.)

Swift is very explicit by design about requiring that variables be initialized, because assumptions about the content of uninitialized references are one of the ways that programs in C (and some other languages) can become buggy. So, you need to explicitly ask for an [SKSpriteNode?] array that contains 64 nils:

var sprites = [SKSpriteNode?](repeating: nil, count: 64)

This actually returns a [SKSpriteNode?]?, though: an optional array of optional sprites. (A bit odd, since init(count:,repeatedValue:) shouldn't be able to return nil.) To work with the array, you'll need to unwrap it. There's a few ways to do that, but in this case I'd favor optional binding syntax:

if var sprites = [SKSpriteNode?](repeating: nil, count: 64){    sprites[0] = pawnSprite}

The best you are going to be able to do for now is create an array with an initial count repeating nil:

var sprites = [SKSpriteNode?](count: 64, repeatedValue: nil)

You can then fill in whatever values you want.

In Swift 3.0 :

var sprites = [SKSpriteNode?](repeating: nil, count: 64)

This question has already been answered, but for some extra information at the time of Swift 4:

In case of performance, you should reserve memory for the array, in case of dynamically creating it, such as adding elements with Array.append().

var array = [SKSpriteNode]()array.reserveCapacity(64)for _ in 0..<64 {    array.append(SKSpriteNode())}

If you know the minimum amount of elements you'll add to it, but not the maximum amount, you should rather use array.reserveCapacity(minimumCapacity: 64).