How to open your app in Settings iOS 11

Here is the code you're looking for, I guess:

if let url = URL(string: UIApplicationOpenSettingsURLString) {    if UIApplication.shared.canOpenURL(url) {        UIApplication.shared.open(url, options: [:], completionHandler: nil)    }}

And in addition, the updated version for swift 5 :

if let url = URL(string: UIApplication.openSettingsURLString) {    if UIApplication.shared.canOpenURL(url) {        UIApplication.shared.open(url, options: [:], completionHandler: nil)    }}

Swift 4.2, iOS 12

Opening just the settings is possible with the function below:

extension UIApplication {    ...    @discardableResult    static func openAppSettings() -> Bool {        guard            let settingsURL = URL(string: UIApplication.openSettingsURLString),            UIApplication.shared.canOpenURL(settingsURL)            else {                return false        }        UIApplication.shared.open(settingsURL)        return true    }}

Usage: UIApplication.openAppSettings()

But be careful to NOT use "non-public URL scheme", such as: prefs:root= or App-Prefs:root, because otherwise your app will be rejected. This happened to me recently since I was trying to have a deeplink to the wifi section in the settings.

And if you want to make it work for both, older and newer iOS-versions, then do:

if let url = URL(string:UIApplicationOpenSettingsURLString) {    if UIApplication.shared.canOpenURL(url) {        if #available(iOS 10.0, *) {            UIApplication.shared.open(url, options: [:], completionHandler: nil)        } else {            UIApplication.shared.openURL(url)        }    }}