How to use openURL for making a phone call in Swift?
I am pretty sure you want:
UIApplication.sharedApplication().openURL(NSURL(string: "tel://9809088798")!)(note that in your question text, you put tel//:, not tel://).
NSURL's string init expects a well-formed URL. It will not turn a bunch of numbers into a telephone number. You sometimes see phone-number detection in UIWebView, but that's being done at a higher level than NSURL.
EDIT: Added ! per comment below
A self-contained solution in Swift:
private func callNumber(phoneNumber:String) { if let phoneCallURL:NSURL = NSURL(string:"tel://\(phoneNumber)") { let application:UIApplication = UIApplication.sharedApplication() if (application.canOpenURL(phoneCallURL)) { application.openURL(phoneCallURL); } }}Now, you should be able to use callNumber("7178881234") to make a call.