Sort array of objects by two properties

Yes there is a very simple way using the Array.sort()

Code:

var sorted = array.sorted({ (s1, s2) -> Bool in    if s1.isPriority && !s2.isPriority {        return true //this will return true: s1 is priority, s2 is not    }    if !s1.isPriority && s2.isPriority {        return false //this will return false: s2 is priority, s1 is not    }    if s1.isPriority == s2.isPriority {        return s1.ordering < s2.ordering //if both save the same priority, then return depending on the ordering value    }    return false})

The sorted array:

true - 10true - 10true - 12true - 12true - 19true - 29false - 16false - 17false - 17false - 17false - 18

Another a bit shorter solution:

let sorted = array.sorted { t1, t2 in    if t1.isPriority == t2.isPriority {      return t1.ordering < t2.ordering    }   return t1.isPriority && !t2.isPriority }

Here is a simple statement to do this sorting:

var sorted = array.sort { $0.isPriority == $1.isPriority ? $0.ordering < $1.ordering : $0.isPriority && !$1.isPriority }

Conform to Comparable! 😺

extension Sortable: Comparable {  static func < (sortable0: Sortable, sortable1: Sortable) -> Bool {    sortable0.isPriority == sortable1.isPriority    ? sortable0.ordering < sortable1.ordering    : sortable0.isPriority  }}

Which will allow for:

sortableArray.sorted()