Which is the Swift equivalent of isnan()?
It's defined in the FloatingPointNumber protocol, which both the Float and Double types conform to. Usage is as follows:
let d = 3.0let isNan = d.isNaN // Falselet d = Double.NaNlet isNan = d.isNaN // True
If you're looking for a way to make this check yourself, you can. IEEE defines that NaN != NaN, meaning you can't directly compare NaN to a number to determine its is-a-number-ness. However, you can check that maybeNaN != maybeNaN
. If this condition evaluates as true, you're dealing with NaN.
Although you should prefer using aVariable.isNaN
to determine if a value is NaN.
As a bit of a side note, if you're less sure about the classification of the value you're working with, you can switch over value of your FloatingPointNumber
conforming type's floatingPointClass
property.
let noClueWhatThisIs: Double = // ...switch noClueWhatThisIs.floatingPointClass {case .SignalingNaN: print(FloatingPointClassification.SignalingNaN)case .QuietNaN: print(FloatingPointClassification.QuietNaN)case .NegativeInfinity: print(FloatingPointClassification.NegativeInfinity)case .NegativeNormal: print(FloatingPointClassification.NegativeNormal)case .NegativeSubnormal: print(FloatingPointClassification.NegativeSubnormal)case .NegativeZero: print(FloatingPointClassification.NegativeZero)case .PositiveZero: print(FloatingPointClassification.PositiveZero)case .PositiveSubnormal: print(FloatingPointClassification.PositiveSubnormal)case .PositiveNormal: print(FloatingPointClassification.PositiveNormal)case .PositiveInfinity: print(FloatingPointClassification.PositiveInfinity)}
Its values are declared in the FloatingPointClassification enum.
The accepted answer works but when I first saw it I wasn't exactly clear because of the example and i didn't know that NaN is an acronym for "not a number"
.
Here's an example from Apple for anyone who isn't clear:
let x = 0.0let y = x * .infinity // y is a NaN because .infinity is not a numberif y.isNan { print("this is NaN") // this will print} else { print("this isn't Nan")}