Symfony 2 FOS User Bundle Bootstrap modal AJAX Login

I have found the solution. Here is what I added to my javascript,

<script>    $(document).ready(function(){        $('#_submit').click(function(e){            e.preventDefault();            $.ajax({                type        : $('form').attr( 'method' ),                url         : '{{ path("fos_user_security_check") }}',                data        : $('form').serialize(),                dataType    : "json",                success     : function(data, status, object) {                    if(data.error) $('.error').html(data.message);                },                error: function(data, status, object){                    console.log(data.message);                }            });        });    });</script>

And here is my onAuthenticationFailure method from my handler,

public function onAuthenticationFailure(Request $request, AuthenticationException $exception) {    $result = array(        'success' => false,         'function' => 'onAuthenticationFailure',         'error' => true,         'message' => $this->translator->trans($exception->getMessage(), array(), 'FOSUserBundle')    );    $response = new Response(json_encode($result));    $response->headers->set('Content-Type', 'application/json');    return $response;}

I think that it was the URL from my Ajax method that was wrong. Thank you for your advices.

I guess what youre looking for is this: Symfony2 ajax login.

your javascript would look sth. like this:

$('#_submit').click(function(e){        e.preventDefault();        $.ajax({            type        : $('form').attr( 'method' ),            url         : $('form').attr( 'action' ),            data        : $('form').serialize(),            success     : function(data, status, object) {                if (data.sucess == false) {                    $('.modal-body').prepend('<div />').html(data.message);                } else {                    window.location.href = data.targetUrl;                }            }    });

You also have to modify the isXmlHttpRequest-part of your onAuthenticationSuccess-Method:

[...]if ($request->isXmlHttpRequest()) {            $targetUrl = $request->getSession()->get('_security.target_path');            $result = array('success' => true, 'targetUrl' => targetUrl );            $response = new Response(json_encode($result));            $response->headers->set('Content-Type', 'application/json');            return $response;        }[...]