Add multiple extensions in one filetypes mac - tkinter/filedialog/askopenfilename Add multiple extensions in one filetypes mac - tkinter/filedialog/askopenfilename tkinter tkinter

Add multiple extensions in one filetypes mac - tkinter/filedialog/askopenfilename


It seems that you must separate the wildcard patterns with a space rather than ; (verified on Python 3.5.1):

from tkinter import filedialog# add `, initialdir="..."` to set the initial directory shown in the dialogfiledialog.askopenfilename(filetypes=[("Excel files", ".xlsx .xls")])

Note:

  • While "*.xlsx *.xls" would work too (at least on Windows and macOS), the initial * isn't necessary.[1]
  • Whether .* or *.* works (no filter) seems to be platform-dependent; omitting filetypes is the better option in that case.
  • Similarly, the behavior of matching part of the base filename - something like foo.txt or foo*.txt - appears to be platform-dependent: on Windows, these do work, with a prepended * (*foo.txt and *foo*.txt), whereas on macOS they seem to match nothing.

If the platform-dependent behaviors are instead / also lined to different tkinter versions, do let us know.


[1] Jakub Bláha reports that "*.xlsx *.xls" didn't actually work for him in Python 3.7.4 on Windows 10 version 1903 (though I don't see the same problem); to be safe, omit the * if not needed.


At least on Windows, if you want to be able to open multiple filetypes but always only one at a time, your code has to look like this:

filedialog.askopenfilename(filetypes=[("Excel file","*.xlsx"),("Excel file 97-2003","*.xls")])

If you want to be able to select both file types at the same time without switching between them, they need to have the same name.

filedialog.askopenfilename(filetypes=[("Excel file","*.xlsx"),("Excel file", "*.xls")])


Multiple extensions on Windows 10 work for me like this. For example searching for python files.

py_exts = r"*.py  *.py3 *.pyc  *.pyo  *.pyw  *.pyx  *.pyd  *.pxd  *.pyi  *.pyi  *.pyz  *.pywz *.rpy  *.pyde *.pyp  *.pyt  *.xpy  *.ipynb"  filename = filedialog.askopenfilename(initialdir=SEEN,                                              title="Select a File",                                              filetypes=(("video files",                                                          video_exts),                                                         ("python files", py_exts),                                                         ("all files",                                                          "*.*")))