How to pass Model action to View button in Tkinter MVC?

If the button has no command, then nothing will ever happen.It needs to have a command, that calls a function of the controller.

Then, the controller will execute this command, either by communicating with the model, or by triggering another view.

Since the button is going to call a function of the controller, it needs to be aware of it.Let's assume that you passed it as parameter, and that you want the button to trigger controller.Action, controller being an (the?) instance of Controller.

Here is how your view should look like:

class View():    def __init__(self, master, controller):        self.master = master        self.controller = controller        b = Button(master, text='Hello', command=self.controller.Action())        b.pack()

Then, clicking on the button will result in a call to Action.

You can use this in the controllers init() function:

self.view.b.bind("<Button>",self.action)

That way you don't have to use a command in the view.

I'm still trying to figure out how to do this for menubuttons... so this might be a bit of a struggle if it's new for you (like it is for me).

Edit:As requested, a small sample:

import tkinter as tk# Data stuffclass Model():    def __init__(self):        pass          # GUIclass View():    def __init__(self, master):        self.master = master        self.b = tk.Button(self.master, text="quit")        self.b.pack()# Logic of the appclass Controller():    def __init__(self):        self.root = tk.Tk()        self.model=Model()        self.view=View(self.root)        self.view.b.bind("<Button>",self.action)        self.run()    def run(self):        self.root.mainloop()    def action(self,event):        self.root.destroy()if __name__ == '__main__':    c = Controller()