Tkinter dropdown Menu with keyboard shortcuts?

import tkinter as tkimport sysclass App(tk.Tk):    def __init__(self):        tk.Tk.__init__(self)        menubar = tk.Menu(self)        fileMenu = tk.Menu(menubar, tearoff=False)        menubar.add_cascade(label="File", underline=0, menu=fileMenu)        fileMenu.add_command(label="Exit", underline=1,                             command=quit, accelerator="Ctrl+Q")        self.config(menu=menubar)        self.bind_all("<Control-q>", self.quit)    def quit(self, event):        print("quitting...")        sys.exit(0)if __name__ == "__main__":    app = App()    app.mainloop()

Maybe

from tkinter import *import tkinter.filedialog as filedroot = Tk()root.title("My Python Tkinter Application")root.minsize(800,600)def openfile():    fn = filed.askopenfilename(filetypes=[("Text Files","*.txt")], title="Open File")    f = open(fn, "r").read()    print(f)def init():    menu = Menu(root)    filemenu = Menu(menu)    filemenu.add_command(label="Open (⌘O)", command=openfile)    menu.add_cascade(label="File", menu=filemenu)    root.config(menu=menu)def key():    print("Key Pressed: "+repr(event.char))root.bind("<Key>", key)

In this code press ctrl+e to exit the programmme

from tkinter import *class MainApp:    def __init__(self, root):        self.root = root        self.menubar = Menu(self.root)        self.fileMenu = Menu(self.menubar, tearoff=False)        self.menubar.add_cascade(label="File", menu=self.fileMenu)        self.fileMenu.add_command(label="Exit", accelerator="Ctrl+E")        self.root.config(menu=self.menubar)        self.root.bind_all("<Control-e>", lambda event: self.root.quit())        self.root.mainloop()if __name__ == "__main__":    MainApp(Tk())