How do you get inferred type from a typescript AST?
The compiler knows about that type---bar.foo() doesn't compile---how can I programmatically get the type?
The AST
is not the complete story for TypeChecking. You need a TypeChecker
.
The simplest solution is to create a program (some docs https://basarat.gitbooks.io/typescript/content/docs/compiler/program.html) and then use program.getTypeChecker
(more docs https://basarat.gitbooks.io/typescript/content/docs/compiler/checker.html) 🌹
As far as I can tell this does the trick:
// load typechecker for fileconst program = ts.createProgram([filename], {});const typeChecker = program.getTypeChecker()// now get astconst ast = ts.createSourceFile(filename, filecontents, ts.ScriptTarget.ES6, true))// get node under question using ts.forEachChild (not shown here)const node = // ...const type = typeChecker.getTypeAtLocation(node);
The only weird part is that in a variable declaration, the "node" must be the value
(aka FirstLiteralToken) and not the label
(aka Identifier)---otherwise, the type is undefined.For example, if the file contents are const foo = 123
, passing the node for "foo" to typeChecker#getTypeAtLocation won't work. You must pass the node for "123"