Bash script: always show menu after loop execution
Make it beautiful and userfriendly ;-)
#!/bin/bashwhile :do clear cat<<EOF ============================== Menusystem experiment ------------------------------ Please enter your choice: Option (1) Option (2) Option (3) (Q)uit ------------------------------EOF read -n1 -s case "$REPLY" in "1") echo "you chose choice 1" ;; "2") echo "you chose choice 2" ;; "3") echo "you chose choice 3" ;; "Q") exit ;; "q") echo "case sensitive!!" ;; * ) echo "invalid option" ;; esac sleep 1doneReplace the echos in this example with function calls or calls to other scripts.
just modified your script like below. its working for me !
#!/bin/bash while true do PS3='Please enter your choice: ' options=("Option 1" "Option 2" "Option 3" "Quit") select opt in "${options[@]}" do case $opt in "Option 1") echo "you chose choice 1" break ;; "Option 2") echo "you chose choice 2" break ;; "Option 3") echo "you chose choice 3" break ;; "Quit") echo "Thank You..." exit ;; *) echo invalid option;; esac done done
You can also do something like:
#!/bin/bashPS3='Please enter your choice: 'options=("Option 1" "Option 2" "Option 3" "Quit")select opt in "${options[@]}"do case $opt in "Option 1") echo "you chose choice 1" ;; "Option 2") echo "you chose choice 2" ;; "Option 3") echo "you chose choice 3" ;; "Quit") break ;; *) echo invalid option;; esac counter=1 SAVEIFS=$IFS IFS=$(echo -en "\n\b") # we set another delimiter, see also: https://www.cyberciti.biz/tips/handling-filenames-with-spaces-in-bash.html for i in ${options[@]}; do echo $counter')' $i let 'counter+=1' done IFS=$SAVEIFSdone