convert exponential to decimal in python

I imagine you have a list rather than an array, but here it doesn't make much of a difference; in 2.6 and earlier versions of Python, something like:

>>> L = [2.32313e+07, 2.1155e+07, 1.923e+07, 11856, 112.32]>>> for x in L: print '%f' % x... 23231300.00000021155000.00000019230000.00000011856.000000112.320000

and in 2.6 or later, the .format method. I imagine you are aware that the numbers per se, as numbers, aren't in any "format" -- it's the strings you obtain by formatting the numbers, e.g. for output, that are in some format. BTW, variants on that %f can let you control number of decimals, width, alignment, etc -- hard to suggest exactly what you may want without further specs from you.

In awk, you can use printf.

You can use locale.format() to format your numbers for output. This has the additional benefit of being consistent with any locale-specific conventions that might be expected in the presentation of the numbers. If you want complete control at the specific place where you do the output, you'd be better of with the print "format" % vars... variant.

Example:

>>> import locale >>> locale.setlocale(locale.LC_ALL, "")'C/UTF-8/C/C/C/C'>>> locale.format("%f", 2.32313e+07, 1)'23231300.000000'

In answer to the last part of your question, awk can use the same printf format:

awk '{printf "%f\n",$1}' exponential_file

Where exponential_file contains:

2.32313e+072.1155e+071.923e+0711856112.32

You can do the conversion into a variable for use later. Here is a simplistic example:

awk '{n = sprintf("%f\n",$1); print n * 2}' exponential_file