Datetime Unix timestamp contains milliseconds

From the documentation, you can see that timestamps in Python are expected to be calculated in seconds, not milliseconds: http://docs.python.org/2/library/time.html#time.time

You've probably gone over that already.

It should be reasonably easy to slice off the last 3 digits of your timestamps though:

datetime.fromtimestamp(str(unix_timestamp)[0:-3])

You might also wish to do some string length checking to verify that they are 13 digits long instead of just 10 though:

if len(unix_timestamp) == 13:    unix_timestamp = float(str(unix_timestamp)[0:-3])datetime.fromtimestamp(unix_timestamp)

By the way, on some systems, timestamps must be between 1970 - 2038. That could also cause a ValueError.

If you wish to keep milliseconds, you can store them like this:

milliseconds = 0if len(unix_timestamp) == 13:    milliseconds = int(unix_timestamp[-3:])    unix_timestamp = float(unix_timestamp[0:-3])the_date = datetime.fromtimestamp(unix_timestamp)the_date += timedelta(milliseconds=milliseconds)

The fromtimestamp method expects a unix timestamp and that has a resolution of seconds. You will have to convert your time in two steps:

mytime = datetime.fromtimestamp(timestamp/1000)                 .replace(microsecond = (timestamp % 1000) * 1000)

Explanation by @Jordan is very nice but i think there might be error in parsing which i was facing so i coorected the code as below:

datetime.datetime.fromtimestamp(float(str(timestamp)[0:-3]))