delete everything before pattern including pattern using awk or sed
Just set a flag whenever the pattern is found. From that moment on, print the lines:
$ awk 'p; /pattern/ {p=1}' file111 222 333 444 555666 777 888 999 000Or also
awk '/pattern/ {p=1;next}p' fileIt looks for pattern in each line. When it is found, the variable p is set to 1. The tricky point is that lines are just printed when p>0, so that the following lines will be printed.
This is a specific case of How to select lines between two patterns? when there is no such second pattern.
sed '1,/pattern/d' fileworks for your example.
sed '0,/pattern/d' fileis more reliable.